Starting with the information that is given:
Two options, due to the lack of punctuation:
a=1b=2z=26
-or-
a=1
b=2
z=36
p=(not defined)
q=(not defined)
r=(not defined)
Therefore, all we can assert from the given information is that p+q+r = p+q+r (the variables can be rearranged without altering the (unknown) value, because of the commutative property of addition.
a, b and z are not used in the equation, so their values are irrelevant.
p, q and r are not defined, so we cannot assume any value for any of the variables in the equation. Well, we could assume, but it would be just that - an assumption, and an unfounded assumption at that. There was not enough information provided to draw any more concrete conclusion.
y= 3/6 which reduces to 1/2
2y+26 = 28 2y = 28-26 2y = 2 y = 1
26 - 21 = 5 or 24 - 23 = 1
10 ( x = -3)
1 plus 1 equals one fact
y= 3/6 which reduces to 1/2
2y+26 = 28 2y = 28-26 2y = 2 y = 1
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
26 - 21 = 5 or 24 - 23 = 1
10 ( x = -3)
26
1 plus 1 equals one fact
26
2 times 13 equals 26. 1 times 26 also equals 26.
In base six arithmetic: 16 + 26 + 36 = 106 Another contributor's answer: 3+2+1 = 10
4
1 plus 1 equals 1 (in Boolean logic) 1 plus 1 equals 10 (in base 2)