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Use conservation of linear momentum. Before firing the bullet the total momentum was zero (assuming you were not moving), therefore, after firing the bullet, the total momentum must needs also be zero. Therefore, after the shot, m1v1 + m2v2 = 0, where m1 and v1 correspond to the pistol, and m2 and v2 correspond to the bullet.
Recoil.
Made in 1920. Would need to know detailed information as to its condition and originality. Even a non-factory recoil pad would hurt the value. Digital pictures would be a big help. sales@countrygunsmith.net
Buy a slip on recoil pad. I did this fir an 11-87 and it worked great. I believe that if you contact Remington, this gun can be changed to a full size stock for a modest charge. See this link to Remingtons site. http://remington.custhelp.com/cgi-bin/remington.cfg/php/enduser/std_adp.php?p_faqid=83&p_created=954356014&p_sid=DQ3j1pYi&p_accessibility=0&p_redirect=&p_lva=&p_sp=cF9zcmNoPTEmcF9zb3J0X2J5PSZwX2dyaWRzb3J0PSZwX3Jvd19jbnQ9MywzJnBfcHJvZHM9MCZwX2NhdHM9JnBfcHY9JnBfY3Y9JnBfcGFnZT0xJnBfc2VhcmNoX3RleHQ9eW91dGg*&p_li=&p_topview=1
He uses muscular energy to impart forward momentum to the rock,in the amount of MRVR = 20 kilogram-miles per second.Since the total momentum of the boy-skateboard-rock system is conserved,the boy and skateboard must acquire the same amount of momentum in theopposite direction.M(B+S)V(B+S) = 20V(B+S) = 20 / M(B+S)= 20 / 60 = 1/3 mile per second.(The questioner's typo ... writing "miles per second" where he meant "meters per second" ...makes this quite a story ! The boy's pitch is no ordinary fling, endowing the rock with over32,000 joules of kinetic energy. Thereafter, the rock ... or whatever is left of it after itsincendiary trip through the atmosphere at 20 miles per second ... is well on its way to themoon, while the boy and his skateboard recoil backwards at a mere 1,200 miles per hour.But the physics and the arithmetic are sound, even if they have no resemblance to reality.)
muzzle velocity is the velocity of bullet and recoil velocity is the velocity of gun.
Whether you need it depends on the specific situation, but the recoil velocity does affect the total energy.
When a gun is fired, the projectile goes one way, the gun goes in the opposite direction. That is recoil. Recoil velocity would be the speed at which the gun moves when it recoils. Since the gun is heavier than the projectile, it will recoil more slowly than the projectile moves.
Depdends on weight of gun, caliber, load and velocity of projectile
Depends entirely on the caliber, weight and velocity of the projectile along with the weight of the firearm
No way to answer without knowing the weight of the weapon, weight of the projectile, velocity of the projectile
When you fire a rifle,the recoil kick is introducing you to Newton's Third Law.If you you don't hold the rifle properly to absorb the recoil in your whole body, the recoil will leave a nasty bruise mark; (mv) recoil = (mv) bullet. You want to minimize the recoil velocity by maximizing the recoil mass=your rifle + your body. Getting the [proper stance and grip will raise the recoil mass the reduce the impact on your body.
There may be recoil from the hose.
assuming that you talking about a .308 Winchester or the 7.62 NATO round recoil is factor of pure physics the lighter the weapon the greater the free recoil (kick).the heavier the bullet the greater the kick. the higher the velocity the more kick.there are many factors involved in calculating the recoil of any firearm.what does the gun weigh ?what is the barrel length? what is the bullet weight? is the gun a bolt action or auto-matic ? is it gas or recoil operated ? does it have a recoil reducer of some type? how effective is this recoil reducer? knowing the interior ballistics of a cartridge is only the beginning of calculating the recoil and barrel flip of any firearm. in my observation over many years most .308 guns have recoil effect of between 7-15 foot pounds of free recoil energy.
I think this would be a problem of momentum. p=mv so if the momentum of the bullet is 20 (.01x200=20) then the recoil velocity should equal 10 m/sec (2x10=20). Good old Newtons 3rd Law.
The M9 is a SHORT RECOIL, SEMIAUTOMATIC & MAGAZINE fed. MAJOR COMPONENTS: Slide Assembly, Barrel & Locking Block Assembly, Recoil Spring & Recoil Spring Guide, Receiver, & Magazine. CALIBER: 9x19mm (9mm NATO) LENGTH:8.54" WIDTH: 1.5" WEIGHT: 33.86 oz w/out mag, 40.89 oz w/15 round magazine. BARREL LENGTH: 4.92" RIFILING: Right Hand 6 Groove. MUZZLE VELOCITY: 1230.30 feet per second MUZZLE ENERGY: 420ft lbs MAX. RANGE: 1800 Meters.
.351 km/hr