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By the Law of Conservation of Momentum, the total momentum after the collision must be the same as the total momentum before the collision.

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Q: If a moving ball rolls into a stationary ball the total momentum of both balls after the collision will be?
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Where does kinetic energy go after it is used?

If you're suggesting something like an auto accident, the energy of the collision is used to deform materials in the structural elements of the vehicle(s). It also heats them. The primary design features of cars includes a lot of thought to where the energy of a collision can go. Bumpers collapse, body panels and their strengthening members fold and become compressed, and a top or roof can collapse down. All this sinks ("sucks up") energy. And if it all works in an optimal way, you can climb out and walk away.


Comparison between elastic and inelastic collision?

In an elastic collision, all initial kinetic energy is fully restored as final kinetic energy. where nothing is converted into noise, heat or any other form of energy. In an inelastic collision, kinetic energy is "lost" to thermal or sound energy.


Can potential energy ever be less than kinetic energy?

The answer to both of your questions lies in the different nature of both quantities, momentum and kinetic energy. Momentum is a vector, kinetic energy is a scalar. This means that momentum has a magnitude and a direction, while kinetic energy just has a magnitude. Consider the following system: 2 balls with equal mass are rolling with the same speed to each other. Magnitude of their velocities is the same, but the directions of their velocities are opposed. What can we say about the total momentum of this system of two balls? The total momentum is the sum of the momentum of each ball. Since masses are equal, magnitudes of velocities are equal, but direction of motion is opposed, the total momentum of the system of two balls equals zero. Conclusion: the system has zero momentum. What can we say about the total kinetic energy of this system? Since the kinetic energy does not take into account the direction of the motion, and since both balls are moving, the kinetic energy of the system will be different from zero and equals to the scalar sum of the kinetic energies of both balls. Conclusion: we have a system with zero momentum, but non-zero kinetic energy. Assume now that we lower the magnitude of the velocity of one of the balls, but keep the direction of motion. The result is that we lower the total kinetic energy of the system, since one of the balls has less kinetic energy than before. When we look to the total momentum of the new system, we observe that the system has gained netto momentum. The momentum of the first ball does not longer neutralize the momentum of the second ball, since the magnitudes of both velocities are not longer equal. Conclusion: the second system has less kinetic energy than the first, but has more momentum. If we go back from system 2 to system 1 we have an example of having more kinetic energy, but less momentum. I hope this answers your question Kjell


Did Isaac Newton make Newton Balls?

I can not tell you why he made it but I can tell you about it. Newton's cradle can be modeled with simple physics and minor errors if it is incorrectly assumed the balls always collide in pairs. If one ball strikes 4 stationary balls that are already touching, the simplification is unable to explain the resulting movements in all 5 balls, which are not due to friction losses. For example, in a real Newton's cradle the 4th has some movement and the first ball has a slight reverse movement. All the animations in this article show idealized action (simple solution) that only occurs if the balls are not touching initially and only collide in pairs.


In the case of Newton's Cradle it is known that once set in motion the balls will eventually stop moving Why?

The reasons are the same as they are for any similar oscillatory system. It is largely because energy is dissipated as heat wherever there is friction: at the ends of the strings and where the balls collide. Hence the total amount of energy within the system falls until the oscillation is no more. Wherever there are resistive forces, there can be no perpetual motion without violating the Conservation of Energy principle.

Related questions

When 2 balls collide the momentum of the balls after the collision is explained by?

Conservation of momentum.


How will balls move if they collide and stick together?

Consevation of momentum applies. The final compond mass must have the same momentum as the net momentum of the two balls before the collision. Remember, momentum is a vector and direction is important. For example if the two balls are moving toward each other with the same momentum, the net momentum is zero because they are moving in opposite directions. So the compound ball will not move. Or, if ball 1 is moving left and has a greater momentum then ball 2 ,moving right, then the compound ball will move left. Its momentum will equal the difference between the two momentums because when you add two vectors in opposite directions you subtract their magnitudes. Mechanical energy (potential + kinetic) is not conserved in this collision because some mechanical energy is lost as heat in the collision.


Two balls of masses 500gram and 200 gram are moving at valocities 4m s and 8m s respectively on collision they stick together find the velocity af the system after collision?

The idea is to use conservation of momentum. Calculate the total momentum before the collission, add it up, then calculate the combined velocity after the collision, based on the momentum.


What is the total momentum between two identical balls traveling toward each other at the same speed from opposite directions?

They have identical momentum before the collision . The total momentum will the the same before and after the collision. When the balls collide they will bounce apart both with same force and so the same momentum as originally - but in opposite directions. This assumes no energy loss in an ideal elastic collision.


A 3 kg ball moving to the right at 1.4 m-s collides inelastically with a 2 kg ball at rest What will the velocity of the combined balls be after the collision?

It appears from the question that the balls stick together after the collision. Linear momentum is conserved. The linear momentum is the total of the product of mass and velocity for each of the balls. The linear momentum before is (1.4 x 3) + (0 x 2) = 4.2 kgms-1. The linear momentum after is v x (3 + 2) = 4.2kgms-1, since we know it is conserved. Hence, v = 4.2 / 5 = 0.84ms-1, in the same direction of travel as the 3kg ball was originally moving.


What is the same before and after the collision when Ball A bumps into Ball B?

The total momentum of the two balls.


Describe what happens to the momentum of two billiard balls that collide?

They have identical momentum before the collision . The total momentum will the the same before and after the collision. When the balls collide they will bounce apart both with same force and so the same momentum as originally - but in opposite directions. This assumes no energy loss in an ideal elastic collision.


A collision in which the total momentum and kinetic energy remain constant?

Kinetic energy is only conserved if the collision is elastic. All other collisions will have some loss of kinetic energy even when momentum is conserved.


Definition of Momentum in physics?

The momentum of a moving body is defined as the product of its mass and velocity. Notice that since 'velocity' has a direction as well as a magnitude (is a vector quantity), momentum also has direction as well as magnitude. That's why two billiard balls, moving toward each other each with the same exact speed, can completely stop dead after the collision ... since their velocities are in opposite directions, their momentums are also exactly opposite, and add up to zero.


If two objects collide they each have the same momentum as they had before the collision?

The momentum of this case is equal to the summation of cross product of mass and velocity of both. How ever after the collision, some energy is converted into other form like sound and heat. This phenomena caused the momentum efficiency (e) In this case (masses are equal), e is equal to the ratio of the velovities summation of both masses between after and before hitting each other. e = ((V1'+V2')/(V1+V2));


What is the surface area of 2 touching billiard balls?

The contact area will be different if they are stationary or is the result of an impact, and is affected by the presence of chalk on the balls and the out-of-round condition of each ball. The actual contact area of 2 clean, new stationary balls is less than 0.01 square millimeters. This contact area is much larger for a typical collision.


Where does kinetic energy go after it is used?

If you're suggesting something like an auto accident, the energy of the collision is used to deform materials in the structural elements of the vehicle(s). It also heats them. The primary design features of cars includes a lot of thought to where the energy of a collision can go. Bumpers collapse, body panels and their strengthening members fold and become compressed, and a top or roof can collapse down. All this sinks ("sucks up") energy. And if it all works in an optimal way, you can climb out and walk away.