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Q: If a number is both divisible by 4 and 9 by what other numbers is it divisible?

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972 is one of the numbers that is divisible by both.

Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.

These numbers are not evenly divisible by 6: Any number smaller than 6. Any odd number (not divisible by 2). Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.

It doesn't have a numerical answer. If both numbers are even, one will be divisible by the other.

Numbers are divisible by their factors. Multiples are divisible by their numbers.

The LCM of both numbers is 198

The LCM of both numbers is 18

Numbers are divisible by 6 if they are divisible by both 2 and 3.All even numbers are divisible by 2. Odd numbers are not.To see if a number is divisible by 3, add the individual digits of the number to each other and see if that number is divisible by 3. If it is, then the original number is also divisible by 3.Example: 2712, add 2+7+1+2=12 Is 12 divisible by 3? Yes. Therefore, 2712 is divisible by 3.The number 2712 is also divisible by 2, since it is an even number.Now you know that 2712 is divisible by 6.

All numbers that are multiples of 12 are divisible by both 3 and 4.

Any number that is a multiple of 18 is divisible by 2 and 9.

The lists of numbers divisible by and not divisible by 600 are both infinite.

Any number divisible by 15

Both composite 75 is divisible by 5 112 is divisible by 2 ... and other numbers

For any two numbers, there's always an infinite list of numbers that are divisible by both of them. For 93 and 273, one of them is 8463.

Numbers that are co-prime won't both be divisible by nine.

No. They are composite because they are divisible by two and other numbers.

There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.

All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6

11

numbers which are divisible by both an even number and odd number greater than 1: 6, 10, 12, 14, 18, ...

10 ÷ 2 = 510 ÷ 5 = 2Therefore, the answer is ten

There is no such number. If you have any such number, n, that is divisible by 3 and 5 then n + 15 is larger, and is divisible by both. And you can add another 15 to that number, and then to that, for ever more.

a number is 6. All numbers divisible by both 4 and 15 are the multiples of 4 and 15. Since 4 and 15 have no prime factor in common (4 = 22, 15 = 3 · 5), then the least common multiple of 4 and 15 is equal to their product, namely 4 · 15 = 60. Every other multiple of 4 and 15 is divisible by 60. Thus, if 60 is divisible by a number then all the multiples of 4 and 15 are divisible by that number. Therefore, it is enough to check by which number in the given options is 60 divisible. Only 6 divides 60 and none of the other do. The answer must be (A).

You can continue to generate numbers that are divisible by both 5 and 9 indefinitely. There is no upper limit.

Any number evenly divisible by an even number is also even. A number evenly divisible by an odd number (such as 5) could be either even or odd.