no...for example 18
18 divided by 3=6
18divided by 2=9
18 cant be divided by 12
Any number of the form 84*k, where k is an integer, is evenly divisible.
I BELIEVE IT IS 156 THE SMALLEST NUMBER 4 AND 6 GO INTO IS 12 12 X 13 = 156
Which of the following is a composite number between 57,47,17,2
8xy-12yz=4y(2x-3z)8 and 12 are both divisible by 4, both terms on the lhs (left-hand side) are divisible by y. You can therefore "pull out" or factorize the 4 and the y, and the remainder is (2x-3z).
Yes, for example the trivial case in which the numbers are the same:The GCF of 12 and 12 is 12.This also occurs when one number is divisible by the other:The GCF of 12 and 4 is 4.
Not always because 30 is divisible by 2 and 6 but not by 12
No. Consider 6 itself or 18.
Not always because 18 is divisible by 2 and 6 but not by 12
Answer is 48. Step-by-step instructions: Factors of 4 = 1,2,4. Factors of 12 = 1,2,3,4,6,12. So, let's see 12's first 4 multiples. = 12,24,36,48. Now, let's check 48's Factors. = 1,2,3,4,6,12 It's Factors have both 4 and 12. So, it is the number this is divisible by Both 4 and 12.
Yes, because 12 is divisible by 2 and 6.
If a number is divisible by both three and four, it's divisible by twelve.
The smallest whole number divisible by both 8 and 12 is 24.
lol yeah it is i think
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9
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