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8xy-12yz=4y(2x-3z)

8 and 12 are both divisible by 4, both terms on the lhs (left-hand side) are divisible by y. You can therefore "pull out" or factorize the 4 and the y, and the remainder is (2x-3z).

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15y ago

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Q: How do you factorise 8xy-12yz?
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