8xy-12yz=4y(2x-3z)
8 and 12 are both divisible by 4, both terms on the lhs (left-hand side) are divisible by y. You can therefore "pull out" or factorize the 4 and the y, and the remainder is (2x-3z).
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m(g-a)
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
5(3-2x)
2a(2b-c) :P
What about it? Factorise it?