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Q: If a number is exactly divisible by 11 only then the number is always?

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It is a number only divisible by one and itself.

Two is a prime number so it is only evenly divisible by one and itself.

yes it can only be an even number

293 is not divisible by 5. Only numbers that end on 0 or 5 are exactly divisible by 5.No, it is not.

There is not one. A prime number has exactly two factors, 1 and itself. The only way that a prime number could be divisible by 48 is if 48 were a prime number, which it is not.

Do you mean what is a number that has exactly two factors? If so the answer is a prime number. Eg. 2,3,5,7,11..... They are only divisible by 1 and themselves

Short answer: 2 The only number by which a factor of 4 may always be divided (other than 4) is 2.

Yes, 48 is divisible by 8, exactly 6 times. Any number is divisible by 8, but not all are divisible evenly (that is, with no remainder). The only number that cannot be divided into another is 0 (zero).

No - numbers are only divisible exactly by ten - if they end in a zero !

No number is ever divisible by zero.

There is always a GCF, even if it's only 1.

There is no number, no matter the number of digits, that is only divisible by 2.

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