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Not always because as for example 25 is not evenly divisible by 10 but it is evenly divisible by 5

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0Every number divisible by 10 is divisible by 5.

No. 15, 25, 35, and 1675 are divisible by 5, but not by 10. However, every number divisible by 10 is also divisible by 5.

If a number is divisible by 10 (i.e. 100) then it is also divisible by 5. Ex: 100 by 10, is 10 by 5, is 20 20 by 10 is 2 by 5 is 4 The number of times it is divisible by 5 will always be double the number of times it is divisible by 10, which makes sense because 10 is double 5.

Any number that ends in a zero is divisible evenly by 5 and 10

Always. A number divisible by another is also divisible by all the factors of that number. A number that is divisible by 10 is also divisible by 2 and 5. Take any multiple of 10 and check it. 70/5=14 or 180/5=36

No as 5 is a factor of 10

No. Any number that is divisible by 10 is divisible by 5. It doesn't work the other way.

If a number ends with 0, it is divisible by 10. If a number ends with 5 or 0, it is divisible by 5.

There is no such number.

Because 10 is divisible by both 2 and 5

Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.

Use the divisibility rule for 10. If the number is divisible by 10, then it is obviously also divisible by 5.

There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.

Yes, since 10 is divisible by 5. Likewise, every number which is divisible by 9 is also divisible by 3.

10 is divisible by both 5 and 2, as are any multiples of 10.

10 is divisible by 2 because it goes into 10 5 times. Also 10 is divisible by 5, 5 goes into 10 2 times. Ten is divisible by any real number other than zero.

To check for divisibility, use the modulus, or % operator. If the expression results in zero, then the first number is divisible by the second number. For example, 10%5 equals 0 because 10 is divisible by 5. When the expression does not result in 0, the number is not divisible(10%7=3, so 10 is not divisible by 7).

no 10 is only divisible the end number (in this case 5) is a 0

If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10

445 is divisible by 5 because 445 is a multiple of 5. 445 is not divisible by 9 or 10 because 445 is not a multiple of 9 or 10. 445 is not divisible by 5910 because it is impossible for a number to be divisible by a greater number.

The smallest one would be 10. Since the LCM of 2, 5, and 10 is 10, then all multiples of 10 are divisible by 2, 5, and 10.

Nope, 10 is divisible by 5, 2, and 1. You are looking for the number 12. 12 is divisible by 6.

A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.

Yes. Any number ending in 0 is divisible by 10, which automatically makes it divisible by 5 as well.

There is none. Any number that is divisible by 2 and 5, for example, must also be divisible by 10.

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