(1) L = 7W + 3
(2) 2L + 2W = 54
Substituting (1) in (2) ...
2(7W+3) + 2W = 54
14W + 6 + 2W = 54
16W = 48
W = 3
L = 7x3 + 3 = 24
So, length is 24 and width is 3
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).
A rectangle has two dimensions - length and width. Only if both dimensions are doubled, then the perimeter will be doubled.
2 times (length + width)
The area is the length times the width. The perimeter is two times the length plus two times the width.
Perimeter = 2*(Length + Width) = 2*(24.6 + 12.2) = 2*36.8 = 73.6 units
Its width would be 2cm. To find the missing dimension, divide the perimeter by two, then subtract the known variable.
The perimeter of a rectangle is the distance around the rectangle. The area of a rectangle is the space inside the rectangle. To calculate either one you need the length and the width of the rectangle. To calculate the area multiply the length times the width. To calculate the perimeter add the length+width+length+width (that is the distance all the way around)
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
rectangle with 10" length and 2x-4 width 60" area
The dimensions work out as length = 9 and width = 5
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.