By Euler's formula for the relationship between the number of Vertices, Faces and Edges of a polyhedron,
V + F = E + 2 so 14 + 10 = E + 2 so that E = 22.
No such shape exists. The closest contenders would be: a cylinder - 3 faces, 2 edges, 0 verticies or a cone - 2 faces, 1 edge, 1 vertex
I presume that you mean "16 edges" by "16 sides".An object with 6 faces, 8 corners and 16 edges violates Euler's rule thatfaces + corners = edges + 2(6 + 8 = 14 ≠ 16 + 2) - if it existed, that is.If it had 6 faces, 8 corners and 12 edges it would be a cuboid.
it would have to be a triangle
Any rectangular prism, including a cube, has 8 vertices and 6 faces.
This is an impossible three-dimensional figure. A pyramid has 5 faces and 8 edges but has 5 corners, not 4. A 4-cornered three-dimensional figure has only one itteration: that of a 4 sided pyramid of 6 edges. Since your shape is 5 sided with 8 edges I would say you have got a number wrong there somewhere.
The shape would be impossible. The faces and vertices have to add up to two more than the edges.
The shape you're looking for that has 2 faces, 0 edges, and 0 vertices would be a cylinder.
A rectangle is a two-dimensional shape, so it doesn't have faces in the way that three dimensional shapes have. A rectangle has four edges and four corners.
A pyramid consists of a base and triangular faces that connect the base to a single apex. For a pyramid with ( n ) edges, the number of triangular faces is equal to the number of edges on the base. A pyramid with 10 edges would typically have a triangular base (3 edges), meaning it has 7 edges connecting the apex to the base corners. Therefore, it would have 7 triangular faces.
If it's a pyramid, it has 10 edges.
A cylinder would fit the given description.
Assuming the shape is a simply connected polyhedron, there are 6 faces. A triangular dipyramid, for example.