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If a typical radial engine has a bore of 5.5 inches and a stroke of 5.5 inches what is the area and where is the piston displacement?
Wiki User
∙ 13y ago
This is the formula.
Area = .7854 x bore^2
A = .7854 x 30.25 (5.5^2)
A= 23.75 sq.in
Volume = Area x stroke
23.75 x 5.5 = 130.625 cubic inches.
*This is just one piston. If engine was a nine cylinder then
130.625 x 9 = 1175.625*
Wiki User
∙ 13y ago
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