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If a typical silicon wafer with a diameter of 300 millimeter and a thickness of 0.7 millimeter were to contain an average of 1 x 1016 boron atoms per cm3 how many grams of boron are in this wafer?
Wiki User
∙ 14y ago
I do feel bad about answering this one, it is quite simple. Find the volume, multiply it by the atom density, then divide by avogadro's number, and finally, multiple by the molecular weight of boron.
Assuming this wafer is cylindrical.
Find the volume
Volume = pi*D^2/4*thickness
3.14*(30cm)^2/4*.07cm= 49.48 cm^3
Multiply it by the atom density
Volume*rho.atom
49.48 cm^3*1 X 10^16 atoms/cm^3= 4.948 X 10^17 atoms boron
Then divide by Avogadro's number
Atom/N.a= mol
4.948 X 10^17 atoms/(6.022 141 79(30) × 1023 atoms/mol)= 8.217 X 10^-7 mol
Finally, multiple by the molecular weight of boron.
MW.B = 10.811 g/mol
8.217 X 10^-7 mol*10.811 g/mol= 8.883 X 10^-6 grams = 8.883 micrograms
Wiki User
∙ 14y ago
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