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If a volunteer fire department averages 3.4 fire calls per week and assuming a Poisson distribution what is the probability that the department will receive five or less calls during a given week?
Benson99
Five or less fire calls is: P(0)+P(1)+......+P(5). Formula is: P(x) = (mxe-m)/x! where m=mean & x is number of calls So, P(o) = (3.40e-3.4)/0! = .0334 Likewise P(1)=.1135; P(2)=.1929; P(3)=.2186; P(4)=.1858 & P(5)=.1264. So, P(Five or less fire calls) = .8706
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