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The child will have the disorder, only if the recessive allele from both the parents is transferred to the child. Therefore, the probability is 1/4.
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!
If only one person is a carrier of cystic fibrosis than there is no chance of having a child with it. Both parents have to be carriers and even then there is only a 25% chance. If only one carries than there is a 50% chance that their children will carry but will not have cystic fibrosis.
The probability is 2 - 6
The probability is zero! There is no such thing as "normal". Every child (and adult) has some unique characteristics and that makes them not normal - in that respect.
The child will have the disorder, only if the recessive allele from both the parents is transferred to the child. Therefore, the probability is 1/4.
First child will always prevail from being SS. Some even have AA, but most of the time. Its AS.
50%
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!
There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. Unfortunately there is no readily available research into the genders of seven or more children to establish the experimental probability for such an outcome. However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, then the probability of the seventh child being a girl is 0.48.
25%
Nothing. the law recognizes the legal husband as the legal father of the child.
If only one person is a carrier of cystic fibrosis than there is no chance of having a child with it. Both parents have to be carriers and even then there is only a 25% chance. If only one carries than there is a 50% chance that their children will carry but will not have cystic fibrosis.
By Mendalian principle, one more child will be healthy.
If both parents are carriers on cystic fibrosis, just because two children may have the disease it doesn't mean that say,a further 3 children in future will be "normal". Inheriting genes is like a lottery. I can say though that because cystic fibrosis is recessive, every offspring born under carriers will always have a 75% chance of being phenotypically normal.
Pp x Pp yields PP, Pp, Pp, pp. PP is the only genotype which will cause the phenotypic expression of the gene - symptoms of PKU. Therefore the probability is 1/4 or 25%