60 m/s
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
The sprinter's acceleration is 2 meters per second squared.
Each side of the square is 3 meters in length
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Meters/seconds squared
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
The acceleration of the body is 3 m/s²
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
The sprinter's acceleration is 2 meters per second squared.
Each side of the square is 3 meters in length
Acceleration = (change in speed) divided by (time for the change)Acceleration = (96 - 32) / 8 = 64/8 = 8 meters per second2
"Constant rate" implies there is no acceleration - acceleration is zero.
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
Acceleration = (change in speed) divided by (time for the change) = (25) / (10) = 2.5 meters per second2