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For this we calculation must consider the equation

s=uv + 1/2 at2

Where s = displacement, u= initial velocity, v= velocity, a= acceleration & t=time.

Since initial velocity is is at rest hence 0 we can ignore the uv.

Also the acceleration is gravity or g.

So therefore

s=1/2 gt2

For earth g= 9.812865328 m/s

and t= 5 s

so

s= 1/2*9.812865328*(5)2

s= 122.66m

This answer of course does not take into consideration wind resistance.

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Q: If an object is released from rest and falls for 5 seconds How far did the object fall?
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