Q: If divided by 3 the remainder is 1 and if divided by 100 the remainder is 0 and it has three digits and it is less than 400?

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3 divided by 2 has a remainder of 1. Which is 1 less than 2.

Nothing. The remainder has to be less than the divisor.

18

The remainder is always 31 or less.

1098765433 will have a remainder of 1.

0.0385

0.4

what is the number that has three digits less than 140 has7 factor the sum of the digits of the number is less than 9

37 is the number.

24 is answer.

Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.

29

23 / 7 = 3 R 2, 23 < 40, 23 / 4 = 5 R 3

14. The largest possible number for a remainder is 1 less than the divisor.

114 beacause it's three digits a factor of seven even

That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.

12.5

This is an extremely poor question. There are 28 pairs of numbers and, in less than 10 minutes, I could find reasons why 17 pair were different from the other numbers in the set. A bit more time and I am sure I could do the rest. So here they are: 53 and 72: leave a remainder of 15 when divided by 19. 53 and 77: leave a remainder of 5 when divided by 12. 53 and 82: leave a remainder of 24 when divided by 29. 53 and 87: leave a remainder of 2 when divided by 17. 53 and 95: leave a remainder of 11 when divided by 21. 53 and 97: leave a remainder of 9 when divided by 11. 67 and 95: leave a remainder of 11 when divided by 28. 67 and 87: leave a remainder of 7 when divided by 17. 67 and 97: leave a remainder of 7 when divided by 30. 72 and 82: leave a remainder of 0 when divided by 2 (are even). 72 and 87: leave a remainder of 0 when divided by 3 (multiples of 3). 72 and 95: leave a remainder of 3 when divided by 23. 72 and 97: leave a remainder of 22 when divided by 25. 77 and 95: leave a remainder of 5 when divided by 9. 77 and 97: leave a remainder of 17 when divided by 20. 82 and 95: leave a remainder of 4 when divided by 13. 87 and 95: leave a remainder of 7 when divided by 8.

112

-- Every multiple of 12 has a remainder of 3 when divided by 9.-- The largest multiple of 12 that's less than 220 is (12 x 18) = 216.-- So there are 18 of them.

33

it is 10

10 \ 2

Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.

989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.