A remainder of zero is obtained whenever the number is divided by its factor. For example, when 20 is divided by either 1,2,4,5,10 or 20 the remainder is zero. Every number has 1 as its divisor.Infact, this is the definition of divisor- a number which divides another number to return zero as the remainder.
First note that when you divide any number by the 10, the remainder will be the same number as the units digit. For example, when 26 is divided by 10, the remainder is 6 and when 37832728 is divided by 10, the remainder is 8. For this problem, we just need to know what the units digit of the number 2^400. So let's see if we can see a pattern. 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, and 2^6 = 64. The pattern we are looking for is the value of the units digit. It is 2, 4, 8, 6, 2, 4, 8, 6, and it repeats. Every fourth remainder is 8 and since 400 is a multiple of 4, 2^400 will have 6 as its units whatever the number is and therefore the remainder will be 6. Hope that helps :)
20 if you divide by 17. 19 if you divide by 16. 18 if you divide by 15, 17 if you divide by 14. And so on. In fact any number from 10 to 99. That is, every two digit number.
Yes, it is. It can be determined in moments, without doing the division, by calculating the core digit of the number, which is 9. Every number with a core digit value of 9 is a multiple of 9, and therefore a multiple of 3.
104.697
Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.
Every odd number greater than 1 does that.
A remainder of zero is obtained whenever the number is divided by its factor. For example, when 20 is divided by either 1,2,4,5,10 or 20 the remainder is zero. Every number has 1 as its divisor.Infact, this is the definition of divisor- a number which divides another number to return zero as the remainder.
First note that when you divide any number by the 10, the remainder will be the same number as the units digit. For example, when 26 is divided by 10, the remainder is 6 and when 37832728 is divided by 10, the remainder is 8. For this problem, we just need to know what the units digit of the number 2^400. So let's see if we can see a pattern. 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32, and 2^6 = 64. The pattern we are looking for is the value of the units digit. It is 2, 4, 8, 6, 2, 4, 8, 6, and it repeats. Every fourth remainder is 8 and since 400 is a multiple of 4, 2^400 will have 6 as its units whatever the number is and therefore the remainder will be 6. Hope that helps :)
Because every [whole] number can be divided by '1' without a remainder. ' 1 ' fits into every [whole] number a whole number of times.
Any multiple of 3 can be divided by 3 with no remainder.
Any number is divisible by any number. There is no number that is divisible by any number into a whole number with no remainder other than 0.
20 if you divide by 17. 19 if you divide by 16. 18 if you divide by 15, 17 if you divide by 14. And so on. In fact any number from 10 to 99. That is, every two digit number.
Yes, it is. It can be determined in moments, without doing the division, by calculating the core digit of the number, which is 9. Every number with a core digit value of 9 is a multiple of 9, and therefore a multiple of 3.
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
what does every digit in pnr justify...
104.697