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This would be the simple answer, ignoring air resistance, wind, and other such incooperative forces.

First working out the vertical component of velocity when it hits the floor:

final velocity (v) = ?

Initial velocity (u) = 0

Displacement (s) = 3

Accelleration (a) = g; taken to be 9.81

Using the equationof linear motion v2 = u2 + 2as

v2 = 0 + (2 * 9.81 * 3)

v2 = 58.86

v = 7.672

Now we know that the horizontal component of velocity will be 2.5 ms-1 (ignoring air resistance) so now we have to find out the velocity of the ball when it hits the floor, if it is travelling at a velocity with a downwards vertical component of 7.672ms-1 and a horizontal component of 2.5ms-1

2.52 + 7.6722 = 65.1095

Square rooting that...

Velocity = 8.069ms-1

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Q: If i throw a ball downward from a window at a speed of 2.5 ms How fast will it be moving when it hits the sidewalk 3.0 m below?
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