The GCF is 8.
8x+40
Perimeter of 12" by 8" = 12+8+12+8 = 40 inches.
2 x 2 x 2 = 8 2 x 2 x 2 x 5 = 40
Find a common denominator (40 is a good choice in this case):3/10 + 1/5 + 1/8 = 3x4/10x4 + 1x8/5x8 + 1x5/8x5= 12/40 + 8/40 + 5/40= 12+8+5/40= 25/40= 5x5/8x5= 5/8
It is m1/5
The GCF is 8.
Find the area of a rhombs with diagonals that measure 8 and 10.
8% of 40 is the same as 0.08 times 40 = 3.2
8 2*8 = 16 5*8 = 40
Perimeter = 12 + 12 + 8 + 8 = 40.
To find 1/5 of 40, divide 40 by 5. 1/5 of 40 = 8
8 divided by 10 gives 10%, which is 0.8. This is simply multiplied by 4 to find 40%, which is 3.2
8 4,2 2,2,2 40 20,2 10,2 5,2,2,2 Select the common factors. 2 X 2 X 2 = 8, the GCF
The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40
The partial products are: 42 * 28 = (40 + 2)*(20 + 8) = 40*20 + 40*8 + 2*20 + 2*8 = 800 + 320 + 40 + 16
8x+40