It is m1/5
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Slopes of parallel lines have the same slope (they are changing at the same rate).Slopes of perpendicular lines have slopes that are the negative inverse of each other, that is, their product is -1. (The slope of a vertical line is therefore undetermined, not infinity. There is no slope s that times 0 equals -1.)---Let m1 be the slope of line one and m2 be the slope of line two. Then:If the lines are parallel, then their slopes are equal, so m1 - m2 = 0.If the lines are perpendicular, then their slopes are negative inverses of each other, so= m1 - (-1/m1)= m1 + 1/m1= (m12 + 1)/m1
If the slopes are m1 and m2 then m1*m2 = -1 or m2 = -1/m1.
inversetan ( |m1 - m2/1+m1m2| )
Using only a compass & straight edge (classic style), draw a circle around any point on the line. All you need is the two tiny arcs crossing the line. Then taking the two places where your first arcs crossed the line as centers, draw two bigger circles around those points. Note that each circle will each cross the line at two points. You actually need just the two points from each center "toward" the other center. (Don't make the two second circles so big that the radius is greater than the distance between the two points (though this will still work). This will give you two arcs across the line, and they will intersect each other above and below the line. If you then take your straight edge and draw a line through your original line from one of those intersections to the other, this new line will be perpendicular to the original line. Use the link to the Wikipedia article and look at the construction. It's actually the construction of a perpendicular through a line from a point off the original line, but check it out and note the green arcs, which would be your two second arcs from the two centers you found with your first circle. The blue line is the perpendicular to the original (the black) line. m2=-1/m1 where m1=grad of the original line & m2=grad of the line perpendicular to the original line