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What is the perimeter and area of a equalateral triangle whoose base 6m and height is 4m?
This is not an equilateral triangle if height is 4 m the base is 6 m and by Pythagorean theorem the other sides are 5 m perimeter is 6 + 5 + 5 = 16m Area = base x height = 6 x 4 = 24 sq m
What is the equation of a line that passes through the poin -2-4 and -7-1?
(- 2, - 4) and (- 7, - 1)First the slope is needed.m = Y2 - Y1/X2 - X1m = - 1 - (- 4)/- 7 - (- 2)m = - 3/5==========now, point slope form, use these points (- 2, - 4)Y - Y1 = m(X - X1)Y - (- 4) = -3/5[X - (- 2)]Y + 4 = - 3/5(X + 2)Y + 4 = (- 3/5)X - 6/5Y = (- 3/5)X - 26/5===============equation of the line
What are the possible dimensions for the length and the width for a rectangle that has a perimeter of 12 meters if each side is a whole number of meters?
The perimeter of a rectangle is twice the length plus twice the width so half the perimeter is the length plus the width. If the perimeter is 12 m, then the length plus the width must equal 6. The dimensions could therefore be 1 m x 5 m, 2 m x 4 m, 3 m x 3 m (although this would be a square), 4 m x 2 m or 5 m x 1 m.
What is perimeter of a square with 1.25m sides?
Square has 4 sides, so 4 x 1.25 = 5 m
What is the value of 5m2 plus 4n2 if m equals 4 and n equals 3?
5 x 16 + 4 x 9 = 80 + 36 = 116
How many cubic meters in a rectangular solid 5cm long 4cm wide and 3cm high?
100 cm = 1 m volume = length x width x height = 5 cm x 4 cm x 3 cm = 5 ÷ 100 m x 4 ÷ 100 m x 3 ÷ 100 m = 0.00006 cu m = 6 x 10^-5 cu m
What is 4.1 x 10 -5 ns in conventional notation?
That would be 0.000041
What is 4 7 of 56 meters?
4/7 x 56 m = 4/7 x (7x8) m = (4x7x8)/7 m = 4 x 8 m = 32 m
What is the volume of a cylinder with a height of 5 and radius of 2?
The volume of a cylinder equals the area of the base times the height, which equals pi x radius squared x height. Inserting the numbers, V = pi x (2 m.) squared x 5 m. = pi x 4 m. squared x 5 m. = 20 x pi meters cubed or 20 x pi cubic meters.
How do you factor 100m2n?
2 x 2 x 5 x 5 x m x m x n = 100m2n
What is the perimeter and area of a equalateral triangle whoose base 6m and height is 4m?
This is not an equilateral triangle if height is 4 m the base is 6 m and by Pythagorean theorem the other sides are 5 m perimeter is 6 + 5 + 5 = 16m Area = base x height = 6 x 4 = 24 sq m
What is the equation of a line that passes through the poin -2-4 and -7-1?
(- 2, - 4) and (- 7, - 1)First the slope is needed.m = Y2 - Y1/X2 - X1m = - 1 - (- 4)/- 7 - (- 2)m = - 3/5==========now, point slope form, use these points (- 2, - 4)Y - Y1 = m(X - X1)Y - (- 4) = -3/5[X - (- 2)]Y + 4 = - 3/5(X + 2)Y + 4 = (- 3/5)X - 6/5Y = (- 3/5)X - 26/5===============equation of the line
What are the possible dimensions for the length and the width for a rectangle that has a perimeter of 12 meters if each side is a whole number of meters?
The perimeter of a rectangle is twice the length plus twice the width so half the perimeter is the length plus the width. If the perimeter is 12 m, then the length plus the width must equal 6. The dimensions could therefore be 1 m x 5 m, 2 m x 4 m, 3 m x 3 m (although this would be a square), 4 m x 2 m or 5 m x 1 m.
A jogger runs in a straight line with an average speed of 5 meters per s for 4 minutes then finishes with an average speed of 4 meters per s for 3 minutes What is his total displacement?
Displacemant = Velocity x Time First D1 = 5 x 4 x 60 = 1200 m Then D2 = 4 x 3 x 60 = 720 m Total displacement = D1 + D2 = 1920 m
What is perimeter of a square with 1.25m sides?
Square has 4 sides, so 4 x 1.25 = 5 m
How much air is enclosed in a tent with a rectangular base 4 meter by 2.7meter if the height is 5 meter?
As no indication is given as the the height of the walls and the slope of the roof, I'll assume it's a cuboid tent: volume = area_base x height = 4 m x 2.7 m x 5 m = 54 m3
What are the tangent equations to the circle x2 plus y2 -6x plus 4y plus 5 equals 0 at the points where it meets the x axis?
x² + y² - 6x + 4y + 5 = 0→ x² - 6x + 9 - 9 + y² + 4y + 4 - 4 + 5 = 0→ (x - 3)² + (y + 2)² = 8→ The circle has centre (3, -2)It meets the x-axis when y = 0→ x² + 0² - 6x + 4×0 + 5 = 0→ x² - 6x + 5 = 0→ (x - 1)(x - 5) = 0→ x = 1 or 5.For x = 1:The slope of the radius m is (0 - -2)/(1 - 3) = 2/-2 = -1 → slope of the tangent m' = -1/m = -1/-1 = 1→ equation of tangent is:y - 0 = 1(x - 1)→ y = x - 1For x = 5:The slope of the radius m is (0 - -2)/(5 - 3) = 2/2 = 1 → slope of the tangent m' = -1/m = -1/1 = -1→ equation of tangent is:y - 0 = -1(x - 5)→ y = -x + 5→ y + x = 5The tangents have equations y = x - 1 at (1, 0) and y + x = 5 at (5, 0)
