Since [ x = -1 ] causes the whole expression to be equal to zero,
(x+1) must be a factor of the expression.
Divide the expression by (x+1), and you'll be left with the product of the other factors:
(x3 - 3x2 - x + 3) / (x+1) = (x2 - 4x + 3)
That expression can now be factored to find the other two:
(x2 - 4x + 3) = (x - 3) (x - 1)
The other two zeros are:
x = +3
x = +1
10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
enneadecillion
100000000(10 and 7 zeros)
replace the final 3 zeros with 810
here is a list of numbers starting from million to vigintillion 1 plus 6 zeros is 1 million 1 plus 9 zeros is 1 billion 1 plus 12 zeros is 1 trillion 1 plus 15 zeros is 1 quadrillion 1 plus 18 zeros is 1 quintillion 1 plus 21 zeros is 1 sextillion 1 plus 24 zeros is 1 septillion 1 plus 27 zeros is 1 octillion 1 plus 30 zeros is 1 nonillion 1 plus 33 zeros is 1 decillion 1 plus 36 zeros is 1 undecillion 1 plus 39 zeros is 1 duodecillion 1 plus 42 zeros is 1 tredecillion 1 plus 45 zeros is 1 quattuordecillion 1 plus 48 zeros is 1 quindecillion 1 plus 51 zeros is 1 sexdecillion 1 plus 54 zeros is 1 septendecillion 1 plus 57 zeros is 1 octodecillion 1 plus 60 zeros is 1 novemdecillion 1 plus 63 zeros is 1 vigintillion
They are -1, 1 and 5.
x^2 + 11x + 6 has no rational zeros.
10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
enneadecillion
100000000(10 and 7 zeros)
It is called decillion also known as 10 plus 34 zeros
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: 1 plus or minus i times the square root of 2x = 2.4142135623730951ix = 0.4142135623730951iwhere i is the square root of -1
It is called decillion also known as 10 plus 34 zeros
It could be: 1.0*10100 in scientific notation or just 1
1960 plus 3 zeros -1960000 kg . You must be American