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Since [ x = -1 ] causes the whole expression to be equal to zero,

(x+1) must be a factor of the expression.

Divide the expression by (x+1), and you'll be left with the product of the other factors:

(x3 - 3x2 - x + 3) / (x+1) = (x2 - 4x + 3)

That expression can now be factored to find the other two:

(x2 - 4x + 3) = (x - 3) (x - 1)

The other two zeros are:

x = +3

x = +1

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Q: If one of the zeros in x3-3x2-x plus 3 is -1 How do you find the others?
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