4-17i
There are infinitely many polynomials which meet the requirement.The polynomial is x2 + (-a - bi - 3)x + (2a - 2bi - ai + b) = 0and the other root is x = a + bi.There is nothing in the question which requires its coefficients to be real.
There is not enough information. You can't calculate one root on the basis of another root. HOWEVER, if we assume that all the polynomial's coefficients are real, then if the polynomial has a complex root, then the complex conjugate of that root (in this case, 4 - 17i) must also be a root.
No. by definition, the polynomial should contain an integer as exponent and square root 1/2 is not an integer.
True-APEX
That would be (x - 2) ( x - 5) ( x - 5). If you like, you can multiply these polynomials to get a single polynomial in standard form (i.e., not factored).
A root.
1+x2 is a polynomial and doesn't have a real root.
The square root of a polynomial is another polynomial that, when multiplied by itself, yields the original polynomial. Not all polynomials have a square root that is also a polynomial; for example, the polynomial (x^2 + 1) does not have a polynomial square root in the real number system. However, some polynomials, like (x^2 - 4), have polynomial square roots, which in this case would be (x - 2) and (x + 2). Finding the square root of a polynomial can involve techniques such as factoring or using the quadratic formula for quadratic polynomials.
If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.If you mean a math problem, "root" is another word for "solution".The "root" of a polynomial in "x" is any value for "x" which will set the polynomial equal to zero, when evaluated.
None, it involves the square root of a negative number so the roots are imaginary.
68
-2