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Q: If r equals 5ohm and v equals 220v what is the value of current?
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When a resistor is connected to a 25.0 V power supply the current through the resistor is 12.5 A.Calculate the resistance of a second resistor connected in series that reduces the current to 5.00 A.?

R2 = 3 ohms Explanation: For a circuit you can use ohms law where: V=I*R Where V is the voltage difference throughout the surface, I is the current, and R is the total resistance of the circuit. In your case you want to find the resistance so you have to change the formula to: R=V/I R of first circuit = 25volts/12.5amps = 2 ohms R of second circuit= 25 volts / 5 amps = 5 ohms The resistors here are connected in series which means that the resistance of the two can be added together. This gives you: Rtot= R1+R2 we found R of the first resistor by calculating the resistance in the first circuit. We also found Rtot which is the resistance in the second circuit, when you connect the two resistors together in series. Rtot=2 ohms+R2 5ohm=2ohms+R2 R2 = 3 ohms If the resistors where connected in parallel you cannot simply add the resistance. In that case: (1/Rtot)=(1/R1)+(1/R2) Hope that helps