For this problem the equation you need is s = ut + 1/2ft2, where s = distance travelled, u = initial speed, f = acceleration, and t = time. Assuming the object is stationary before it drops, u = 0. f as you say is 980 cm/sec2, but as the result is going to be large I suggest you work in meters and so f = 9.8 m/sec2. t = 20.
Then s = 1/2 x 9.8 x 202 = 1960 meters.
The velocity v at the end of 20 seconds is given by v2 = 2fs, so v = 196 m/sec
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
Acceleration has a dimensionality of length/time^2, so if you were measuring the distance in meters and the time in seconds, the acceleration would be m/s^2.
It is impossible to determine acceleration simply from time and distance.
85
Acceleration= distance / velocity squared
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
object to fall with an approximate acceleration of 9.8 seconds.
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
Acceleration has a dimensionality of length/time^2, so if you were measuring the distance in meters and the time in seconds, the acceleration would be m/s^2.
Gravity exerts a force; the Second Law states that such a force will cause an acceleration, which can be calculated as:a = F/m (acceleration = force divided by mass).
distance (s) = 1/2 acceleration (a) x time (t) squared or s = 1/2 at^2.; a = gravity acceleration = 9.81m/s/s so time is 1.1 seconds
Use the formula for constant acceleration; in the simplest case, where the initial velocity is zero, it is simply:distance = (1/2) times acceleration x time squared You can use 9.8 meters/second squared for acceleration; the distance will then be in meters.
The acceleration will be equal to the acceleration due to gravity. Unless otherwise stated, one can assume this to be 9.81 meters/seconds It has nothing to do with the mass of the stone.
known to be seconds pendulum,the length would be almost 1m when acceleration due to gravity is 9.8m/s2
It is impossible to determine acceleration simply from time and distance.
Speed, or velocity, is measured in distance per second; it is the rate of change of distance with time.Acceleration is the rate of change of velocity with time, or distance per second per second, which is distance per seconds squared,