For this problem the equation you need is s = ut + 1/2ft2, where s = distance travelled, u = initial speed, f = acceleration, and t = time. Assuming the object is stationary before it drops, u = 0. f as you say is 980 cm/sec2, but as the result is going to be large I suggest you work in meters and so f = 9.8 m/sec2. t = 20.
Then s = 1/2 x 9.8 x 202 = 1960 meters.
The velocity v at the end of 20 seconds is given by v2 = 2fs, so v = 196 m/sec
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
Acceleration has a dimensionality of length/time^2, so if you were measuring the distance in meters and the time in seconds, the acceleration would be m/s^2.
It is impossible to determine acceleration simply from time and distance.
85
The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.
The acceleration of the ball is about 9.8 m/s^2, which is the acceleration due to gravity.
The distance can be calculated using the formula: distance = 0.5 * acceleration due to gravity * time^2. Given that the time taken is 3.000 seconds, with an assumed acceleration due to gravity of approximately 9.81 m/s^2, the distance can be calculated as approximately 44.145 meters.
For objects falling under constant acceleration (such as gravity), the distance an object travels each second is determined by the formula d = 0.5 * a * t^2, where "d" is the distance, "a" is the acceleration, and "t" is the time in seconds. This means that the distance traveled each second will increase quadratically as time passes.
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
The distance the apple falls can be calculated using the formula: d = 0.5 * g * t^2, where d is the distance, g is the acceleration due to gravity (9.81 m/s^2), and t is the time taken for the fall (1.4 seconds). Plugging in the values, the apple falls approximately 9.8 meters.
The depth of the mine can be calculated using the formula: distance = 1/2 * acceleration due to gravity * time squared. Given the time is 6 seconds and the acceleration due to gravity is about 9.8 m/s^2, the depth of the mine would be approximately 176.4 meters.
object to fall with an approximate acceleration of 9.8 seconds.
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
Acceleration has a dimensionality of length/time^2, so if you were measuring the distance in meters and the time in seconds, the acceleration would be m/s^2.
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
Gravity exerts a force; the Second Law states that such a force will cause an acceleration, which can be calculated as:a = F/m (acceleration = force divided by mass).