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Suppose the seven numbers are a,b,c,d,e,f and g

The arithmetic mean of all 7 is 10. So the sum of all seven ie a+b+c+d+e+f+g is 10*7 = 70.

The arithmetic mean of the fist six a to f is 11. So their sum (a+b+c+d+e+f) is 11*6 = 66.

So, g = (a+b+c+d+e+f+g) - (a+b+c+d+e+f) = 70-66 = 4

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