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Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
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Open the compass to a width greater than half the length of AB.Place the compass point at A.Draw arcs above and below the line AB.Move the compass point to B WITHOUT changing the compass setting.Draw arcs above and below AB to intersect them at X and Y.Join XY.XY is the perpendicular bisector of AB.7. Celebrate the successful completion of the task!
The formula to find the area of the segment is given below. It can also be found by calculating the area of the whole pie-shaped sector and subtracting the area of the isosceles triangle △ACB.Formula for the area of a segment of a circle where:C is the central angle in DEGREES R is the radius of the circle of which the segment is a part.π is Pi, approximately 3.142sin is the trigonometry Sine function.
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Answer: 22 units
13.6 units
13 units
15.2 units
9 units
the andser is 9
Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.
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radius
8
Not enough information has been given to find the tangent BC but it will be perpendicular or at right angles to the radius of the circle.
If available, a protractor or a right drawing triangle can be used. If restricted to ruler and compass, a right angle can also be constructed to a given line segment by drawing a circle, with a radius less than the length of the line segment but more than half that length, with each end of the line segment as a center and connecting the two points of intersection of the two circles above and below the line. The line connecting to two intersections of these circles will form as right angle to the line segment.