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If the diameter of the dart board is 36 centimeters what is the approximate circumference (Use 3.14 for .)?
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What is the density of a board whose dimensions are 5.54 centimeters by 10.6 centimeters by 199 centimeters and whose mass is 28.6 kilograms?
well the volume of the board is 5.54*10.6*199 = 11686.076 cubic cm. and this volume of board weighs 2860 grams. Thus 1 cubic cm of the board would weigh 0.245 grams so the density is 0.245 g/cc
What is the volume of a board that measures 1.8 centimeters by 8.8centimeters by 30.5 centimeters?
483cm3Multiply 1.8x8.8x30.5 = 483.12 = about 483. Multiply (cm)(cm)(cm) = cm3
What do you use to measure circumference?
Suppose you are given a bangle and you are supposed to measure the circumference. OK? First place it on a paper fixed to a board. Using a fine pencil mark its boundary outer if outer circumference is required. Now draw one chord. Mark AB. Using protractor draw a line perpendicular to the chord at B. Name as BC. Join AC. Measure AC. Multiply AC by 3.14. You would get the required circumference nearly to the accurate one.
What is the density of a board whose dimensions are 5.54 centimeters x 10.6 centimeters x 199 centimeters and whose mass is 28.6?
So the answer is 2.447357008 x10 -03 g/cm cubed. Explanation: a) 5.54 cm times 10.6 cm times 199 cm = 11686.076 (volume= length times width times height) b) density = mass/volume so 28.6 divided by 11686.076 = 2.447357008 x10 -03
What word can be put at the front of board to make a compound word?
card+board hard+board head+board cup+board
A sheet of foam board is 0.5 centimeters thick how many sheets of the board can be stacked in a space that is 12.5 centimeters high?
25
What is the volume of a board that measures 1.8 centimeters by 8.8 centimeters by 30.5 centimeters?
volume of board = L * b * h volume = 1.8 X8.8 X 30.5 =483.12 cm ^ 3
What is the density of a board whose dimensions are 5.54 centimeters by 10.6 centimeters by 199 centimeters and whose mass is 28.6 kilograms?
well the volume of the board is 5.54*10.6*199 = 11686.076 cubic cm. and this volume of board weighs 2860 grams. Thus 1 cubic cm of the board would weigh 0.245 grams so the density is 0.245 g/cc
Which one is more precise for a skateboard centimeters or dekameters?
skate board
What is the size of the A board?
overall diameter 451mm plus or minus 3mm
What is the volume of a board that measures 1.8 centimeters by 8.8centimeters by 30.5 centimeters?
483cm3Multiply 1.8x8.8x30.5 = 483.12 = about 483. Multiply (cm)(cm)(cm) = cm3
What is the name of the distance that goes from the center to the circumference of a circle?
THE RADIUS. For further clarification, message me on my message board. Thanks!
What area of the card can be seen if a picture 12 centimeters by 7 centimeters is framed on the card board 18 centimeters by 11 centimeters?
In terms of their areas, Visible Card = Total Card - Picture = 18*11 - 12*7 = 198 - 84 = 104 cm2.
What is the Size of cornhole game hole?
It is 6 inches in diameter located in the center of the board and 9 inches from the top of the board to the center of the hole. For cornhole board design ideas check out: http://www.cornholeace.com/cornhole-board-designs.php
What is the density of a board whose dimensions are 5.54 centimeters x 10.6 centimeters x 199 centimeters and whose mass is 28.6 grams?
In this case.......... Density = mass in grams/centimeters cubed 5.54 cm * 10.6 cm * 199 cm = 11686.076 cm^3 Density = 28.6 grams/11686.076 cm^3 = 0.00245 grams/cm^3
What do you use to measure circumference?
Suppose you are given a bangle and you are supposed to measure the circumference. OK? First place it on a paper fixed to a board. Using a fine pencil mark its boundary outer if outer circumference is required. Now draw one chord. Mark AB. Using protractor draw a line perpendicular to the chord at B. Name as BC. Join AC. Measure AC. Multiply AC by 3.14. You would get the required circumference nearly to the accurate one.
What is the average weight of a 25 year old pine tree in nz?
The weight of a pine is estimated by calculating the board footage of the tree. To do this it is necessary to have the length and circumference of the logs. To find the weight, one will need to multiply the diameter of the small end of the log by the length of the log. This is then multiplied by 0.37. 50.93 is added to this total. This results on the predicted weight in pounds. There are many factors, such as moisture content, that can affect these numbers.
