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The answer is 45 and 81. To find it out you need to use double algebra. 1. (x+y)-(x-y)=90 x-x=0 y+y=2y/2= 1y=y 90/2= 45 y=45 2. (x+y)+(x-y)=162 y-y=0 x+x=2x 2x/2= 1x=x 162/2=81 3. check your work x+y-x-y=90 81+45-81-45=90- x+y+x-y+=162 81+45+81-45=162 81+45= 126 81-45=36 126+36=162 That is how you find the answer.

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Q: If the difference of the sum and difference of two numbers is 90 and if the sum of the sum and difference is 162 what are the numbers?
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