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Q: If the equation of a circle is x2 plus y2 equals 49 what is its radius?

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Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..

Radius = 1111

9

8

If that equals 16 then the radius is 4

Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.

The radius is sqrt(12) = 3.464 (rounded)

That's the equation of a circle with its center at the origin and a radius of 8.

x^2+y^2=36

The ' 1 ' in that equation is the radius.

3 (which is the sqrt of 9)

Centre = (0,0), the origin; radius = 11

A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6

3x² + 3y² = 75

The graph of that equation is a circle, centered at the origin, with radius = 2 .

5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.

sqrt 36 ie 6

It is the equation of a circle with radius of 6 and its center at the origin.

Centre of circle: (4, -2) Slope of tangent: 1 Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2

x2 +y2 = R2 =16 = radius 2 R = 4

The centre is (3,-1) and the radius is sqrt(10).

I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.

The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.

x^2 + y^2 = r^2

If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2