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The period of a 20 kHz waveform is 1 / 20 kHz, or 50 uS. If the waveform is logic 1 for 30 uS, then it is logic 0 of 20 uS, and the duty cycle is 60%.

Simply subtract from 30 from 50 to get 20. Also, compare 30 against 50 to get 60%

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Q: If the frequency of a rectangular waveform is 20 kHz and it is logic 1 for 30µsec. What is the duty cycle of the waveform and How long does the signal remain a logic 0?
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