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Suppose the width is w cm

Then length is 2w + 6 cm

So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12

Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm

And then, l = 2w + 6 = 32 + 6 = 38 cm

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Q: If the length of a rectangle is 6 cm longer than twice the width and that the perimeter of the rectangle is 108 cm then what is the width and the length?
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