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The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

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Q: The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?

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A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.

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98 square feet

Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter

The length of the rectangle is 18cm. The width of the rectangle is 9cm.

Related questions

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in

Length = (Perimeter - twice width) / 2

If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.

A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.

156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.

Area is length times width, perimeter is twice the sum of length and breadth.

The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.

The length is 20 units and the width is 10 units

12 meters

20 cm

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