The scale or scaling factor.
Two polygons are similar if:the ratio of the lengths of their corresponding sides is the same, andtheir corresponding angles are equal.
The perimeters of two similar polygons have the same ratio as the measure of any pair of corresponding sides. So the ratio of the measure of two corresponding sides of two similar kites with perimeter 21 and 28 respectively, is 21/28 equivalent to 3/4.
i dont kno but qwamane is cool looking though
The ratio of their perimeters will be 3:1, while the ratio of their areas will be 9:1 (i.e. 32:1)
If two polygons are similar then the ratio of their perimeter is equal to the ratios of their corresponding sides lenghts?
It can be any number that you like, but once chosen, it remains the same for each pair of corresponding sides.
If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.
The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63
One factor that polygons have is the scale factor which is the ratio of the lengths of two corresponding sides of similar polygons. This would only pertain to two or more polygons of course. You could also look at a single polygon and find the GCF of the lengths of its sides. So for example if you have a 3,4,5 triangle, the GCF is 1. If you have a 6,8,10 triangle it is 2.
They are the same.
The sacle factor between two shapes is the same as the ratio of their perimeters.
Area = length x length Therefore the ratio of areas of two similar objects is the square of the ratio of lengths. Lengths - 1 : 41 Areas - 12 : 412 = 1 : 1681
If the lengths are in the ratio 3:5, then the surface areas are in the ratio 9:25.
Three sided polygons would be triangles. Triangles that have the same shape (same angle measures) but are different sizes (different side lengths) would be called similar triangles. In similar triangles, corresponding sides have lengths in the same ratio. If triangle ABC is similar to triangle DEF, then: AB/DE = BC/EF = AC/DF.
Whatever the ratio of perimeters of the similar figures, the areas will be in the ratios squared. Examples: * if the figures have perimeters in a ratio of 1:2, their areas will have a ratio of 1²:2² = 1:4. * If the figures have perimeters in a ratio of 2:3, their areas will have a ratio of 2²:3² = 4:9.
If the ratio of side lengths is 49 (that is 49 to 1) then the ratio of their volumes is 493 to 1, which is 117,649 to 1.
The ratio of their surface areas is the square of the ratio of the lengths. Since the ratio of the lengths is 4-1, then the ratio of the surface areas is 4^2-1^2 or 16-1.
The ratio is 27 : 1331.
As volume is length x length x length, cube the ratio of the lengths, thus: Ratio of lengths = 2 : 5 ⇒ Ratio of volumes = 23 : 53 = 8 : 125