x=2, 3, 4...
8
-52x <= 7 (-52x)/(-52) >= 7/(-52) {divide both sides by -52, and reverse the inequality when dividing by a negative. x >= -7/52 There is no largest integer value for x. If the question was ... greater than or equal to ... then the solution would be x <= -7/52, and the largest integer value would be -1.
3x + 6y = 47 6y = -3x + 47 y = -3x/6 + 47/6 y = (-3x + 47)/6 Since we are looking for positive integer, 3x (x > 0) cannot be greater than 47, the possibilities of the numerator are 42, 36, 24, 18, 12, and 6, so that - 3x must be -5, -11, -23, -29, -35, and -41. Since any of them are not multiples of -3, we can not find any pair of positive integers that satisfy the equation. So x and y cannot be both positive integers.
Integers are n, n + 1 and n + 2, so 3n + 3 = 13 + 2n Subtract 2n from each side: n + 3 = 13 Subtract 3 from each side: n = 10 Job done.
(1) First draw the line y = -x + 5.To do that, find two points that lie on the line. Well, when x = 0, y = 5, so plot (0,5) on the plane. When x = 1, y = 4, so plot (1,4). Now draw the only straight line that goes through both of those points. Because the inequality allows for points to lie on the line itself (that's the "or equals to" part), you can make the line solid. If it were just "greater than" (and not equals to) you would draw a dotted line.(2) Shade the correct side of the line.This line divides the plane in two. One side is all the points that satisfy the inequality; on the other side of the line none of the points satisfy the inequality. We will shade in the side that satisfies the inequality. To figure out which side it is, pick a point not on the line, like (0,0). Plug it into your inequality:y >= -x + 50 >= 0 + g0 >= 5This is not true, so shade the side of the plane that does not contain the origin.
No.
"x3" is not an inequality. An inequality will have one of the following signs: less-than, less-than-or-equal, greater-than, greater-than-or-equal. for example: 3x - 5 < 15
It depends upon the inequality. All points on the line are those which are equal, thus:If the inequality is (strictly) "less than" () then the points on the line are not included; howeverif the inequality is "less than or equals" (≤) or "greater than or equals" (≥) then the points on the line are included.
0
Yes, when the inequality has a less that or equal to sign, or a greater than sign or equal to sign, then the equal sign can be replaced and get a solution that is common to both the equation and the inequality. There can also be other solutions to the inequality, where as the solution for the equation will be a valid one.
Yes, and no. The solution set to an inequality are those points which satisfy the inequality. A linear inequality is one in which no variable has a power greater than 1. Only if there are two variables will the solution be points in a plane; if there are more than two variables then the solution set will be points in a higher space, for example the solution set to the linear inequality x + y + z < 1 is a set of points in three dimensional space.
The answer to this question is 14. The reason why is becasue 14 is greater than 14
If the inequality is > (greater than) or >= (greater than or equal to), then there are an infinite number of solutions. So let the inequality be < (less than) or <= (less than or equal to) x = 1: 5y <= 16 so y = 1, 2 or 3 x = 2: 5y <= 12 so y = 1 or 2 x = 3: 5y <= 8 so y = 1 x >= 4: 5y <= 4 no solution. So whether the inequality is < or <= there are 6 ordered pairs.
An inequality has no magnitude. A number can be greater than or equal to -5, but not an inequality.
No. If x greater than or equal to 4 it must be 4 or higher; negative 4 is lower than 4
An inequality requires an inequality sign, usually "less than", "less-than-or-equal", "greater than", or "greater than or equal". Assuming one of these inequality signs is between the "4x" and the "12", for example: 4x < 12, just divide both sides by 4. Just as when you solve equations, the idea is to isolate the variable on one side.
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