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Does the equation 3x plus 6y equals 47 have a solution in which x and y are both positive integers?
3x + 6y = 47
6y = -3x + 47
y = -3x/6 + 47/6
y = (-3x + 47)/6
Since we are looking for positive integer, 3x (x > 0) cannot be greater than 47, the possibilities of the numerator are 42, 36, 24, 18, 12, and 6, so that - 3x must be -5, -11, -23, -29, -35, and -41. Since any of them are not multiples of -3, we can not find any pair of positive integers that satisfy the equation. So x and y cannot be both positive integers.
What else can I help you with?
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Dude, stop trying to cheat on your own maths enrichment task loser.
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