3x + 6y = 47
6y = -3x + 47
y = -3x/6 + 47/6
y = (-3x + 47)/6
Since we are looking for positive integer, 3x (x > 0) cannot be greater than 47, the possibilities of the numerator are 42, 36, 24, 18, 12, and 6, so that - 3x must be -5, -11, -23, -29, -35, and -41. Since any of them are not multiples of -3, we can not find any pair of positive integers that satisfy the equation. So x and y cannot be both positive integers.
y = -2.5 is a equation. And solution to the equation is finding the value of the variable. If we see the equation y is already equal to -2.5 which is the solution to the equation.
Dude, stop trying to cheat on your own maths enrichment task loser.
If you mean 28 = 7+y then the solution of the equation is y = 21
If: 4x = x+15 Then: x = 5
(0, 6.5) is one option.
2
There are 6 such triples.
x^2 + x = 110. x(x + 1) equals x squared + x.
The rule in dividing integers is to divide the absolute values. Two positive integers or two negative integers equals positive product. If one integer is positive and the other is negative, the product is negative.
181 is a prime so 1 times 181 = 181 is the only solution with positive integers.
The first three positive integers, 1, 2, and 3, satisfy this condition.
y = -2.5 is a equation. And solution to the equation is finding the value of the variable. If we see the equation y is already equal to -2.5 which is the solution to the equation.
5x-2=13 +2 +2 5x=15 x=3
r=0 is the solution...
Negative times negative equals positive.
A positive... in basic math (integers).
An equation never equals a number, but its solution often does.-- An equation with a solution of six: [ 3x - 14 = 4 ]-- An equation with a solution of three: [ 14 - 10x = -16 ]-- An equation with both solutions: [ x2 - 9x + 20 = 2 ]An equation that equals 6 is 10 - 4 = 6An equation that equals 3 is 10 - 7 = 3