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If the sum of 2 complex numbers is 4 and their product is 13 what are the 2 numbers?
Wiki User
∙ 11y ago
To solve:
x+y = 4
x*y = 13
x=4-y, so
(4-y)*y = 13 iff
y^2 - 4y + 13 = 0 iff
(y-2)^2 = -9 iff
y-2 = +- 3i
y = 2 +- 3i
e.g., x = 2+3i, y = 2-3i
Wiki User
∙ 11y ago
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If the sum of 2 numbers is 4 and the product of these numbers is 13 what are these 2 numbers?
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