Have the second number be greater than the first.
Look at the numbers starting with the first, then the second. They are the same 98. Look at the third numbers, they are the same 9. Then the fourth number, the first number has 9 and the second has an 8. So the first number is the greater. You can also subtract them and if you need to get a positive number, the top number is greater.
Read 2 numbers. If first is larger than second, display second, else display first. That's for the smallest. For the largest reverse the two. For each of the other two, it's easier to just create a variable, call it largest. Initialize it to a very small number, say -1. As you read each number, compare it to largest. If the number is larger than largest, set largest equal to the number. When you finish each list of numbers, then print largest. Best answer Read 2 numbers. If first is larger than second, display second, else display first. That's for the smallest. For the largest reverse the two. For each of the other two, it's easier to just create a variable, call it largest. Initialize it to a very small number, say -1. As you read each number, compare it to largest. If the number is larger than largest, set largest equal to the number. When you finish each list of numbers, then print largest.
Have the second number be greater than the first.
One option for comparing two numbers is to subtract the first number from the second number. If the result is less than zero, the first number is larger. If the result is greater than zero, the second number is larger. If the result is zero, the numbers are equal. Another option (for positive numbers) would be to divide the first number by the second number. If the result is greater than one, the first number is larger. If the result is less than one, the second number is larger. If the result is one, the numbers are equal. This rule flips if you are comparing negative numbers.
Every second number greater than 2 is an even number.
6.03 is greater than 6.00, as long as you did not round off the 6.0 number. since all the numbers before the 3 are the same, and the number 3 is greater than the number 0 in second decimal place
A number is greater than another number if it is more positive than the second number. 21.1 is more positive than 20. If you want to think of it in terms of the number line: If you write the number line horizontally with negative numbers to the left, zero in the middle and positive numbers to the right a number is greater than another if it is to the right (on the number line) than the second. 21.1 is to the right of 20, so 21.1 is greater than 20.
Initially assume the maximum is equal to the first number. Then compare the maximum to the second number; if the second number is larger than the temporary maximum, assign the second number to the maximum. Repeat for the third number.If you use a for loop, and an array, you can easily expand the program to get the largest out of much larger sets of numbers.
It seems quite complicated - and confusing - to try to do this using only the ternary operator. I suggest you use any method to sort the three numbers using an array (bubble sort should be appropriate, since there are only a few numbers), then take the second number. Note that this method can easily be extended to finding the largest, second-largest, third-largest, etc. number, from among a set of any size.
You put all the numbers in order(smallest to largest) then cross off the first the last then the second then the second to last and so on the middle number is the median.
A positive number is greater than a negative number. If a positive number is greater than another, the corresponding negative numbers are smaller. For example, since 4 > 3, -4 < -3. For two positive numbers: The number with more digits is greater. If they have the same number of digits, the number with the greater first digit is greater. If they are equal, look at the second digit, which will decide which number is greater, and so forth, up to the last digit. For example, 12500 is greater than 12480: they have the same number of digits, the first two digits are the same, but the third digit is the tie-breaker. For numbers with decimals, first apply the rules above for the whole part. If they are equal, check the first digit after the decimal point, then the second, etc., until you find a "tie-breaker". For example, 0.2522 is more than 0.2517. Once again, the first two digits are the same, the third is the tiebreaker.
If the second number is a multiple of the prime number, than the LCM is the second number. If the second number is not a multiple of the prime number, then the two numbers are relatively prime, and the LCM is the product of the two numbers.
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
Yes, Islam religion followers are the second largest number of followers after Christianity.
You can do this by inspection. If the second number is smaller than the first, their difference is positive. If the second number is greater than the first, then their difference is negative. If the second number is the same as the first number, then their difference is zero.
You use a number of rules:* Positive numbers are greater than negative numbers. To compare two positive numbers: * The number more digits to the left of the decimal point is larger. For example, 200 is greater than 27. * If there is no whole part (no part left of the decimal point), the one with less zeros after the decimal point is larger. For example, 0.03 is greater than 0.0005. * If both of the above are the same, the number which has the largest digit for the first non-zero digit (from the left) is largest. For example, 0.03 is greater than 0.029. * If this first non-zero digit from the left is the same, compare the second digit. If those are the same, compare the third digit, etc. For example, 0.02556 is greater than 0.02541. For negative numbers, the rules above give you the SMALLER number. For example, -0.3 is less than -0.02.
There is no such condition. The algorithm to locate the second largest number in an array of numbers is: Sort the array in descending order. Remove the duplicate values from the array. If there are two or more elements remaining, return the second number. If there is less than two elements remaining, return the NaN value (not a number).
Greater. The second number after decimal is greater so number is greater.
Colombia is the second largest producer of coffee. Brazil is number one.
Thomas Jefferson received the second largest number of electoral votes in 1796 election
No, 8.3 is less than 8.37. When determining which decimal is greater, look at the first number after the decimal point, and whichever number is bigger is the bigger decimal. If both numbers are the same (like in this case) move on to the second decimal place. If there isn't a number in the second decimal place, like with 8.3, assume it's a zero. Since 7 is greater than 0, that makes 8.37 greater than 8.30.