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There is no set of three integers whose sum would make 98, because the middle number would have to equal 98/3 = 32.6 recurring (that is, 32.6666...)

However, taking this average as the middle number, and making the other three numbers equal to n - 1 and n + 1, three numbers with a difference of 1 which combine to equal 98 are:

31.6 recurring (31.6666...)

32.6 recurring (32.6666...)

33.6 recurring (33.6666...)

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13y ago
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Q: If there are three consecutive numbers and the sum is 98 what are the three numbers?
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