6 & 4 And 5 & 5 are the only two possibilities, so 4 chances in 36
or 1 in nine.
If two fair dice were rolled, there would be 36 outcomes. (1,1),(1,2),....,(6,6) The maximum sum would be 12. Therefore, the probability that the total number of spots shown is equal to 15 is zero.
If two twelve side fair dice are rolled, there are 144 possible outcomes. Of those 144 outcomes, there are four (1-4, 2-3, 3-2, and 4-1) that add up to five, So the probability of rolling a sum of five is 4 in 144, or 1 in 36.
Each of the dice has 6 sides. There are 6 x 6 = 36 possible combinations. Of those, the following equal 5: 1 and 4 2 and 3 3 and 2 4 and 1 So the odds of rolling a 5 is 4 chances out of 36 4 / 36 = 1 / 9 That converts to a probability of 0.1111111...
P(6) = 5/36 = 0.138888... ≈ 13.9%When two fair dice are rolled, the sample space (all possible outcomes) has 36equiprobable events:(1,1), (1,2), (1,3), (1,4), (1,5),(1,6), (2,1), (2,2), (2,3), (2,4),(2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5),(4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).There are 5 events where the sum of the dots of each die is equal to 6:(1,5), (2,4), (3,3), (4,2), (5,1).So in two fair dice are rolled the probability that the total number of spots shown is equal to 6 is, P(6) = 5/36 = 0.138888... ≈ 13.9%
6 sides on each dice. Each number on the sides is different, this represents the 1 out of all 6 amounts shown. So this is what you'll do for each dice... 1/6 + 1/6 = 2/6 = 1/3
It should be rolled in the direction as shown in the manual.
As shown in the manual
It is 3/8It is 3/8It is 3/8It is 3/8
Direction shown in manual
in the direction shown in the manual
It is malleability.
In the direction shown in the manual