The sum of their slopes is 0. The product of two lines that are perpendicular with slopes m and -m i= -m^2 Hmmmm... Seems we're both wrong again. The answer is -1. See the link I attached.
When the perpendicular lines are horizontal and vertical.
In that case, the product of the slopes is equal to minus 1.
Given any line L, with slope m, the perpendicular line has slope -m.
Take any two lines and look at their slopes. -- If the slopes are equal, then the lines are parallel. -- If the product of the slopes is -1, then the lines are perpendicular.
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
Slopes of perpendicular lines will be opposite reciprocals. This means that the slopes have opposite signs and that one is 1/ the other. For example, 2 and -1/2.
When two lines are perpendicular to each other the product of their slopes is equal to -1.m1*m2 = -1
The slopes of two perpendicular lines are negative inverses of each other. In other words, the two slopes when multiplied together equal -1.
negative reciprocal slopes ---> the lines are perpendicular equal slopes ---> the lines are parallel
Yes, as long as the negative slopes are both equal.
if slope is given as m then perpendicular slope is -1/m (negative inverse)
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