If water freezes at 273 Kelvin and 32 F and it boils at 373 K and 212 F how do you solve for the linear relationship between the Kelvin and Fahrenheit temperature scales?

Answer 1

For Kelvin as measure of temperature interval (and not specific temperature):

(373 - 273) Kelvins (K) = (212 - 32) F 0

or,

for 1 Kelvin temperature interval,

1 K = 1.8 F o (for temperature interval)

As specific temperature,

K = C o + 273.16 ...... (1)


and

C 0 = (F o - 32) x 5/9 ...(2)

Then, substitute for C o from eq 2 in 1 :

K = (F o - 32) x 5/9 + 273.16

or

K = F o x 5/9 + 255.382 (for specific temperature)

Answer 2

its kelvin temperature.

Answer 3

32 F