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If we multiply the cross sectional area of the trough by the speed of the water in the trough, we get the volume of water per second that is running into the tank. 18 cm2 x 3 meters/sec = 18 cm2 x 300 cm/sec = 5400 cm3 /sec As 1 cm3 = 1 ml, the tank is filling at a rat of 5400 ml/sec or 5.4 liters/sec

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Q: If water is running into a tank at the rate of 3 meter per second along a trough with a rectanglar cross section of 18 square centimeters what is the rate at which water is running into the tank?
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