they all have a direct relationship so one of the variables would have to change to effect the other
If the frequency remains constant, then the wavelength increases.
The wavelength stays constant.
The speed of the wave increases, the frequency remains constant and the wavelength increases. The angle of the wave also changes.
This generally happens when a wave moves from one medium into another.Now, the velocity (v) of a wave (mechanical and electromagnetic) is equal to the product of its frequency (f) and wavelength (λ).So, v = f x λThat means if frequency is constant, the wavelength is directly proportional to the velocity.So, if the speed of the wave increases (while frequency remains the same), the wavelength will also increase.
the equation relating wavelength and frequency is : c=n*l ; where n=frequency; l=wavelength; c=velocity of light in vacuum. Now, we know that c is constant always. So, if any one between n and l changes, the other also has to change accordingly so that there product, 'c', remains same, i.e. 3 * 108. Thus, if wavelength of a given wave decreases then its frequency gets increased to bring the product of the new wavelength and new frequency again to 3*108.
If the frequency remains constant, then the wavelength increases.
The wavelength stays constant.
Provided the speed of the wave remains constant, as we increase the frequency of wave then wavelength decreases. Because frequency and wavelength are inversely related.
The wavelength gets shorter. If the propagation speed remains the same, the wavelength (L) decreases by the inverse of the frequency f. For electromagnetic waves c = fL is a constant.
When the frequency DECREASES, the wavelength INCREASES, and vice versa.This assumes the speed of the wave remains constant.
This is not true practically. Theoretically speaking as velocity increases with wavelength remains constant, then frequency has to increase accordingly. Since the formula for velocity is given as: velocity of the wave v = frequency (nu) * wavelength (lamda). In reality the characteristic, namely, frequency remains constant when the speed of the wave changes as it traverses in different medium.
This is not true practically. Theoretically speaking as velocity increases with wavelength remains constant, then frequency has to increase accordingly. Since the formula for velocity is given as: velocity of the wave v = frequency (nu) * wavelength (lamda). In reality the characteristic, namely, frequency remains constant when the speed of the wave changes as it traverses in different medium.
You actually answered your own question. The wavelength remains the same since it is stated as part of the problem. However, the frequency, which I am betting you are more interested in will double. The frequency is releated to the wavelength and the speed of the wave by the following equation f = v/l where f is the frequency, v is the speed, and l is the wavelength. So if the velocity doubles and the wavelength is constant, then the frequency will double.
colour blue ------> red frequency drops, wavelength increases, because speed remains constant and speed=frequency*wavelength
Wave velocity in general = frequency x wavelength As the velocity of the wave remains constant then frequency and wavelength are inversely related So as the wavelength becomes shorter then frequency becomes larger or higher
Assuming the wave propagation speed remains constant, a decrease in wavelength corresponds to an increase in frequency. However there are cases (e.g. waves breaking on a beach) where the wave propagation speed is not constant, the situation gets much more complicated in those cases.
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed