Normally a chord with the diameter of a circle being its biggest chord
The name of a straight line joining two points on the circumference of a circle is a chord.If the line passes through the the centre of the circle it is called a diameter
A chord.
This describes a chord. A chord is a mathematical term on a part of the circle. A chord uses any 2 points in a circle, not matter if they are away from the diameter line or not, they just have to be inside the circle. If you connect the 2 points you have chosen, it gives you a chord. A chord can look like a line segment. .______. This is a line segment, on the left.
Let's say you want to draw a hexagon with each side measuring 2 inches. Take a compass and draw a circle with a radius of 2 inches. With the compass set at the same length (2 inches) start with any point on the circle and measure of 2 inches successively around the circumference of the circle. Join the points with straight lines and you got a hexagon.
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A chord is a straight line joining any 2 points on the circumference of a circle
The points that lie on a circle centered at the origin (0, 0) with a radius of 10 satisfy the equation (x^2 + y^2 = 10^2) or (x^2 + y^2 = 100). This means any point ((x, y)) that meets this equation, such as (10, 0), (0, 10), (-10, 0), and (0, -10), as well as any other points that fall on the circle's perimeter, will lie on the circle. In general, points can be expressed in parametric form as ((10 \cos \theta, 10 \sin \theta)) for any angle (\theta).
If the straight line crosses two points of a circle and goes through the center of the same circle it is the diameter. If these conditions are not met it is a chord.
66 ( 12 nCr 2 )
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.