x= z2 - 3
no
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
If you know the values, just multiply them. "xyz" refers to the product of x, y, and z.
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
no
If one of them and the other One is exactly the same(capital,letters) then it is equal:D
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
y^3
OK< SO< there are many problems that make the answer 38. A few examples:p-36= 74 where "p" equals 38.x+(-19) = 19 where "x" equals 38.i + 5783 = 5821 where "i" equals 38.94 - 56 - x where "x" equals 38.h +3 = 41 where "h" is equal to 38.y3 +19 = 54891 where "y3" equals 54872 where plain "y" would equal 38 (38x38x38 = 54872).And you could come up with a tON more, but that is some possible ones.
If you know the values, just multiply them. "xyz" refers to the product of x, y, and z.
Y3
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
Not sure. There is no particular name for x2 and 2xy (both include x) in x2 + 2xy + y2 + y3
Assuming that your question is x - y^3 Then you would do the following: x = -10 y = -3 -10 - (-3)^3 -10 - (-27) -10 + 27 = 17