y = (a + 12)(x + 3) (line 1)
y = 4ax (line 2)
Since the equation of the second line is in a slope-intercept form, write the equation of the first line in the slope-intercept form, y = mx + b, where m is the slope of the line.
y = (a + 12)(x + 3)
y = a(x + 3) + 12(x + 3)
y = ax + 3a + 12x + 36
y = ax + 12x + 3a + 36
y = (a + 12)x + 3a + 36, where the slope is a + 12
y = 4ax, where slope is 4a
Since the lines are parallel they must have the same slope. So that,
a + 12 = 4a
3a = 12
a = 4
Thus, when a = 4, the parallel lines have a slope of 16.
Their graphs are.
3 times 6 is 18 2 times 5 is 10 18 plus 10 is 28
parallel
They are parallel lines.
If a + b = 6, what is the value of 3a + 3b?
41
Parallel, the slope of the second equation is 4
Their graphs are.
3 times 6 is 18 2 times 5 is 10 18 plus 10 is 28
parallel
No.
With no parentheses, that equals 30.
They are parallel lines.
They are parallel lines.
They are both parallel because the slope or gradient is the same but the y intercept is different.
Yes.
The lines are parallel.