When adding the smallest 2 digit number (= 10) to the smallest 2 digit number (again, 10) the result is a 2 digit number (10 + 10 = 20).
When adding the largest 2 digit number (= 99) to the largest 2 digit number (again, 99) the result is a 3 digit number (99 + 99 = 198).
As you can see, you'll either get a 2 or 3 digit number, but never a 4 digit number.
No. There's no two digit numbers that could do this. The largest two digit number is 99. If you add 99 to itself, you only get 198, which is much smaller than a four digit number.
2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.
You put the four digit number at the top of the three digit number and you do the same thing as you would do with a two digit number with a 3 digit number.
You line up the last numbers and then add it!
It is easier to simply add two one-digit numbers than to mess about with estimation!
32 is the smallest two-digit number that can be multiplied by itself to give a four-digit number. (32x32)=1024
Multiply the three-digit number by the one's digit, or last digit, of the two-digit number. That is your first part. Now multiply by the second-to-last digit, or ten's digit, and multiply the result by 10. That is your second part. Add the two parts and that is your answer.
The digits product of two digit has number four
33 is a two-digit number whose digits add up to 6. 60, 51, 42, 24, 15
Add the two greatest possible four digit numbers. 9999 + 9999
If you're referring to how to solve it manually (e.g. pencil and paper), you'd simply add zeroes to the dividend (the number being divided into) and a decimal to the quotient (the answer) at the point the zeros were added.
-99 is the smallest two digit number.-99 is the smallest two digit number.-99 is the smallest two digit number.-99 is the smallest two digit number.
32 (32 x 32 = 1024)
If its squared rott is 50, the number must be 2500, which is not a 2-digit number.
Even numbers are divisible by two, and half of all numbers are even, so there is a 50 percent chance that a four-digit number is divisible by two.
That is correct. Considering the largest double digit whole number is 99. Unless of course, you mean adding the two digits of a double digit number alongside the two digits of another double digit number, then yes, you will have a 4 digit number. Depends how you interpret the question, and your creativity.
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.